20y^2+51y+28=

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Solution for 20y^2+51y+28= equation:


Simplifying
20y2 + 51y + 28 = 0

Reorder the terms:
28 + 51y + 20y2 = 0

Solving
28 + 51y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(7 + 4y)(4 + 5y) = 0

Subproblem 1

Set the factor '(7 + 4y)' equal to zero and attempt to solve: Simplifying 7 + 4y = 0 Solving 7 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 4y = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 4y = 0 + -7 4y = 0 + -7 Combine like terms: 0 + -7 = -7 4y = -7 Divide each side by '4'. y = -1.75 Simplifying y = -1.75

Subproblem 2

Set the factor '(4 + 5y)' equal to zero and attempt to solve: Simplifying 4 + 5y = 0 Solving 4 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 5y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 5y = 0 + -4 5y = 0 + -4 Combine like terms: 0 + -4 = -4 5y = -4 Divide each side by '5'. y = -0.8 Simplifying y = -0.8

Solution

y = {-1.75, -0.8}

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